(x+3)^2/3-5=-1

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Solution for (x+3)^2/3-5=-1 equation: 


x in (-oo:+oo)

((x+3)^2)/3-5 = -1 // + 1

((x+3)^2)/3-5+1 = 0

((x+3)^2)/3+(-5*3)/3+(1*3)/3 = 0

(x+3)^2-5*3+1*3 = 0

x^2+6*x-6+3 = 0

x^2+6*x-3 = 0

x^2+6*x-3 = 0

x^2+6*x-3 = 0

DELTA = 6^2-(-3*1*4)

DELTA = 48

DELTA > 0

x = (48^(1/2)-6)/(1*2) or x = (-48^(1/2)-6)/(1*2)

x = (4*3^(1/2)-6)/2 or x = (-4*3^(1/2)-6)/2

(x-((-4*3^(1/2)-6)/2))*(x-((4*3^(1/2)-6)/2)) = 0

((x-((-4*3^(1/2)-6)/2))*(x-((4*3^(1/2)-6)/2)))/3 = 0

((x-((-4*3^(1/2)-6)/2))*(x-((4*3^(1/2)-6)/2)))/3 = 0 // * 3

(x-((-4*3^(1/2)-6)/2))*(x-((4*3^(1/2)-6)/2)) = 0

( x-((-4*3^(1/2)-6)/2) )

x-((-4*3^(1/2)-6)/2) = 0 // + (-4*3^(1/2)-6)/2

x = (-4*3^(1/2)-6)/2

( x-((4*3^(1/2)-6)/2) )

x-((4*3^(1/2)-6)/2) = 0 // + (4*3^(1/2)-6)/2

x = (4*3^(1/2)-6)/2

x in { (-4*3^(1/2)-6)/2, (4*3^(1/2)-6)/2 }

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